Base | Representation |
---|---|
bin | 110100101011110101… |
… | …1010010001110001001 |
3 | 101211000221002022102012 |
4 | 1221113223102032021 |
5 | 3323202332124223 |
6 | 123550441145305 |
7 | 11113501050452 |
oct | 1512753221611 |
9 | 354027068365 |
10 | 113140114313 |
11 | 43a89710506 |
12 | 19b1648b235 |
13 | a890c2b805 |
14 | 5694260129 |
15 | 2e22b16c78 |
hex | 1a57ad2389 |
113140114313 has 2 divisors, whose sum is σ = 113140114314. Its totient is φ = 113140114312.
The previous prime is 113140114309. The next prime is 113140114343. The reversal of 113140114313 is 313411041311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 86334893584 + 26805220729 = 293828^2 + 163723^2 .
It is a cyclic number.
It is not a de Polignac number, because 113140114313 - 22 = 113140114309 is a prime.
It is not a weakly prime, because it can be changed into another prime (113140114343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56570057156 + 56570057157.
It is an arithmetic number, because the mean of its divisors is an integer number (56570057157).
Almost surely, 2113140114313 is an apocalyptic number.
It is an amenable number.
113140114313 is a deficient number, since it is larger than the sum of its proper divisors (1).
113140114313 is an equidigital number, since it uses as much as digits as its factorization.
113140114313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 113140114313 its reverse (313411041311), we get a palindrome (426551155624).
The spelling of 113140114313 in words is "one hundred thirteen billion, one hundred forty million, one hundred fourteen thousand, three hundred thirteen".
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