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113140200422 = 256570100211
BaseRepresentation
bin110100101011110101…
…1100111001111100110
3101211000221020200112102
41221113223213033212
53323202342403142
6123550443052102
711113501556504
oct1512753471746
9354027220472
10113140200422
1143a8976a177
1219b16511032
13a890c5ba72
145694283674
152e22b32532
hex1a57ae73e6

113140200422 has 4 divisors (see below), whose sum is σ = 169710300636. Its totient is φ = 56570100210.

The previous prime is 113140200413. The next prime is 113140200539. The reversal of 113140200422 is 224002041311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 224002041311 = 1613913879549.

It is a junction number, because it is equal to n+sod(n) for n = 113140200394 and 113140200403.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28285050104 + ... + 28285050107.

It is an arithmetic number, because the mean of its divisors is an integer number (42427575159).

Almost surely, 2113140200422 is an apocalyptic number.

113140200422 is a deficient number, since it is larger than the sum of its proper divisors (56570100214).

113140200422 is an equidigital number, since it uses as much as digits as its factorization.

113140200422 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56570100213.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 113140200422 its reverse (224002041311), we get a palindrome (337142241733).

The spelling of 113140200422 in words is "one hundred thirteen billion, one hundred forty million, two hundred thousand, four hundred twenty-two".

Divisors: 1 2 56570100211 113140200422