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11314033530452 = 2223122978625331
BaseRepresentation
bin1010010010100100000011…
…1100110001011001010100
31111001121111110010220202122
42210221000330301121110
52440332120040433302
640021332323555112
72245261204145642
oct244510074613124
944047443126678
1011314033530452
113672288a76364
12132889ab2ba98
13640ba77a1723
142b18603dc192
15149485dc13a2
hexa4a40f31654

11314033530452 has 12 divisors (see below), whose sum is σ = 20660409055776. Its totient is φ = 5411059514520.

The previous prime is 11314033530433. The next prime is 11314033530461. The reversal of 11314033530452 is 25403533041311.

It is a super-2 number, since 2×113140335304522 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61489312574 + ... + 61489312757.

It is an arithmetic number, because the mean of its divisors is an integer number (1721700754648).

Almost surely, 211314033530452 is an apocalyptic number.

It is an amenable number.

11314033530452 is a deficient number, since it is larger than the sum of its proper divisors (9346375525324).

11314033530452 is a wasteful number, since it uses less digits than its factorization.

11314033530452 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122978625358 (or 122978625356 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 11314033530452 its reverse (25403533041311), we get a palindrome (36717566571763).

The spelling of 11314033530452 in words is "eleven trillion, three hundred fourteen billion, thirty-three million, five hundred thirty thousand, four hundred fifty-two".

Divisors: 1 2 4 23 46 92 122978625331 245957250662 491914501324 2828508382613 5657016765226 11314033530452