1131403681 has 2 divisors, whose sum is σ = 1131403682. Its totient is φ = 1131403680.

The previous prime is 1131403633. The next prime is 1131403699. The reversal of 1131403681 is 1863041311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 586414656 + 544989025 = 24216^2 + 23345^2 .

It is an emirp because it is prime and its reverse (1863041311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1131403681 - 2¹⁷ = 1131272609 is a prime.

It is a super-2 number, since 2×1131403681² = 2560148578760699522, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1131403781) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565701840 + 565701841.

It is an arithmetic number, because the mean of its divisors is an integer number (565701841).

Almost surely, 2^1131403681 is an apocalyptic number.

It is an amenable number.

1131403681 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131403681 is an equidigital number, since it uses as much as digits as its factorization.

1131403681 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 28.

The square root of 1131403681 is about 33636.3446438521. The cubic root of 1131403681 is about 1042.0115410542.

Adding to 1131403681 its reverse (1863041311), we get a palindrome (2994444992).

The spelling of 1131403681 in words is "one billion, one hundred thirty-one million, four hundred three thousand, six hundred eighty-one".