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1131411402577 is a prime number
BaseRepresentation
bin10000011101101101010…
…111111110111101010001
311000011101000011100110101
4100131231113332331101
5122014112304340302
62223432504532401
7144512300146501
oct20355527767521
94004330140411
101131411402577
113a6913271735
12163337481101
13828cb6b1c11
143ca91151a01
151e66d473287
hex1076d5fef51

1131411402577 has 2 divisors, whose sum is σ = 1131411402578. Its totient is φ = 1131411402576.

The previous prime is 1131411402559. The next prime is 1131411402617. The reversal of 1131411402577 is 7752041141311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1112046175296 + 19365227281 = 1054536^2 + 139159^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131411402577 is a prime.

It is not a weakly prime, because it can be changed into another prime (1131411402677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565705701288 + 565705701289.

It is an arithmetic number, because the mean of its divisors is an integer number (565705701289).

Almost surely, 21131411402577 is an apocalyptic number.

It is an amenable number.

1131411402577 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131411402577 is an equidigital number, since it uses as much as digits as its factorization.

1131411402577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23520, while the sum is 37.

Adding to 1131411402577 its reverse (7752041141311), we get a palindrome (8883452543888).

The spelling of 1131411402577 in words is "one trillion, one hundred thirty-one billion, four hundred eleven million, four hundred two thousand, five hundred seventy-seven".