Base | Representation |
---|---|
bin | 10101000100101111… |
… | …11101001010111111 |
3 | 1002012111112000121110 |
4 | 22202113331022333 |
5 | 141132403422310 |
6 | 5110404533103 |
7 | 550242314445 |
oct | 124227751277 |
9 | 32174460543 |
10 | 11314123455 |
11 | 4886589458 |
12 | 22390b1193 |
13 | 10b402bb0b |
14 | 7948bcb95 |
15 | 46343cd20 |
hex | 2a25fd2bf |
11314123455 has 16 divisors (see below), whose sum is σ = 18107722080. Its totient is φ = 6032491008.
The previous prime is 11314123451. The next prime is 11314123459. The reversal of 11314123455 is 55432141311.
It is an interprime number because it is at equal distance from previous prime (11314123451) and next prime (11314123459).
It is not a de Polignac number, because 11314123455 - 22 = 11314123451 is a prime.
It is a super-2 number, since 2×113141234552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11314123451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 51070 + ... + 158859.
It is an arithmetic number, because the mean of its divisors is an integer number (1131732630).
Almost surely, 211314123455 is an apocalyptic number.
11314123455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11314123455 is a deficient number, since it is larger than the sum of its proper divisors (6793598625).
11314123455 is a wasteful number, since it uses less digits than its factorization.
11314123455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213530.
The product of its digits is 7200, while the sum is 30.
Adding to 11314123455 its reverse (55432141311), we get a palindrome (66746264766).
The spelling of 11314123455 in words is "eleven billion, three hundred fourteen million, one hundred twenty-three thousand, four hundred fifty-five".
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