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1131420130 = 25225150263
BaseRepresentation
bin100001101110000…
…0001100111100010
32220211222002122021
41003130001213202
54304120421010
6304134132054
740015624651
oct10334014742
92824862567
101131420130
11530725765
12276ab102a
13150532189
14aa39b198
15694e08da
hex437019e2

1131420130 has 16 divisors (see below), whose sum is σ = 2037501504. Its totient is φ = 452358000.

The previous prime is 1131420119. The next prime is 1131420137. The reversal of 1131420130 is 310241311.

It is a super-2 number, since 2×11314201302 = 2560223021138433800, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1131420137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2622 + ... + 47641.

It is an arithmetic number, because the mean of its divisors is an integer number (127343844).

Almost surely, 21131420130 is an apocalyptic number.

1131420130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1131420130 is a deficient number, since it is larger than the sum of its proper divisors (906081374).

1131420130 is a wasteful number, since it uses less digits than its factorization.

1131420130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52521.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1131420130 is about 33636.5891552636. The cubic root of 1131420130 is about 1042.0165908182.

Adding to 1131420130 its reverse (310241311), we get a palindrome (1441661441).

The spelling of 1131420130 in words is "one billion, one hundred thirty-one million, four hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 2251 4502 11255 22510 50263 100526 251315 502630 113142013 226284026 565710065 1131420130