Base | Representation |
---|---|
bin | 1010010010100100101110… |
… | …1100110100101011011011 |
3 | 1111001121222000112120212011 |
4 | 2210221023230310223123 |
5 | 2440333002224231341 |
6 | 40021402245530351 |
7 | 2245265524230454 |
oct | 244511354645333 |
9 | 44047860476764 |
10 | 11314213898971 |
11 | 367237086a955 |
12 | 132892b4139b7 |
13 | 640c05c74269 |
14 | 2b187a35012b |
15 | 149496b4db81 |
hex | a4a4bb34adb |
11314213898971 has 2 divisors, whose sum is σ = 11314213898972. Its totient is φ = 11314213898970.
The previous prime is 11314213898957. The next prime is 11314213899019. The reversal of 11314213898971 is 17989831241311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11314213898971 is a prime.
It is a super-2 number, since 2×113142138989712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11314283898971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657106949485 + 5657106949486.
It is an arithmetic number, because the mean of its divisors is an integer number (5657106949486).
Almost surely, 211314213898971 is an apocalyptic number.
11314213898971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314213898971 is an equidigital number, since it uses as much as digits as its factorization.
11314213898971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2612736, while the sum is 58.
The spelling of 11314213898971 in words is "eleven trillion, three hundred fourteen billion, two hundred thirteen million, eight hundred ninety-eight thousand, nine hundred seventy-one".
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