11314214030083 has 2 divisors, whose sum is σ = 11314214030084. Its totient is φ = 11314214030082.

The previous prime is 11314214029961. The next prime is 11314214030111. The reversal of 11314214030083 is 38003041241311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11314214030083 - 2²¹ = 11314211932931 is a prime.

It is a super-2 number, since 2×11314214030083² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11314214034083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657107015041 + 5657107015042.

It is an arithmetic number, because the mean of its divisors is an integer number (5657107015042).

Almost surely, 2^{11314214030083} is an apocalyptic number.

11314214030083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314214030083 is an equidigital number, since it uses as much as digits as its factorization.

11314214030083 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 11314214030083 its reverse (38003041241311), we get a palindrome (49317255271394).

The spelling of 11314214030083 in words is "eleven trillion, three hundred fourteen billion, two hundred fourteen million, thirty thousand, eighty-three".