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113142411200 = 26527213313581
BaseRepresentation
bin110100101011111010…
…0000010111111000000
3101211001002102000011002
41221113310002333000
53323203424124300
6123551002311132
711113526425100
oct1512764027700
9354032360132
10113142411200
1143a8aa3a165
1219b171b84a8
13a891554110
14569469b200
152e22e1c5d5
hex1a57d02fc0

113142411200 has 504 divisors, whose sum is σ = 360117201024. Its totient is φ = 34642944000.

The previous prime is 113142411197. The next prime is 113142411251. The reversal of 113142411200 is 2114241311.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 31593410 + ... + 31596990.

It is an arithmetic number, because the mean of its divisors is an integer number (714518256).

Almost surely, 2113142411200 is an apocalyptic number.

113142411200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113142411200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180058600512).

113142411200 is an abundant number, since it is smaller than the sum of its proper divisors (246974789824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113142411200 is a wasteful number, since it uses less digits than its factorization.

113142411200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3661 (or 3639 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 113142411200 its reverse (2114241311), we get a palindrome (115256652511).

The spelling of 113142411200 in words is "one hundred thirteen billion, one hundred forty-two million, four hundred eleven thousand, two hundred".