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113143023353 is a prime number
BaseRepresentation
bin110100101011111011…
…0011000011011111001
3101211001010120002212102
41221113312120123321
53323204103221403
6123551023353145
711113534554563
oct1512766303371
9354033502772
10113143023353
1143a90318078
1219b174527b5
13a891709939
1456947ba333
152e22eddb88
hex1a57d986f9

113143023353 has 2 divisors, whose sum is σ = 113143023354. Its totient is φ = 113143023352.

The previous prime is 113143023319. The next prime is 113143023379. The reversal of 113143023353 is 353320341311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78625842409 + 34517180944 = 280403^2 + 185788^2 .

It is a cyclic number.

It is not a de Polignac number, because 113143023353 - 210 = 113143022329 is a prime.

It is not a weakly prime, because it can be changed into another prime (113143023053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56571511676 + 56571511677.

It is an arithmetic number, because the mean of its divisors is an integer number (56571511677).

Almost surely, 2113143023353 is an apocalyptic number.

It is an amenable number.

113143023353 is a deficient number, since it is larger than the sum of its proper divisors (1).

113143023353 is an equidigital number, since it uses as much as digits as its factorization.

113143023353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 113143023353 its reverse (353320341311), we get a palindrome (466463364664).

The spelling of 113143023353 in words is "one hundred thirteen billion, one hundred forty-three million, twenty-three thousand, three hundred fifty-three".