Base | Representation |
---|---|
bin | 10101000100110001… |
… | …01001010110110001 |
3 | 1002012111212012212100 |
4 | 22202120221112301 |
5 | 141132430220213 |
6 | 5110412451013 |
7 | 550244000205 |
oct | 124230512661 |
9 | 32174765770 |
10 | 11314304433 |
11 | 48866a2423 |
12 | 2239179a69 |
13 | 10b40932c3 |
14 | 794928b05 |
15 | 463476773 |
hex | 2a26295b1 |
11314304433 has 24 divisors (see below), whose sum is σ = 17217420480. Its totient is φ = 7139901600.
The previous prime is 11314304413. The next prime is 11314304459. The reversal of 11314304433 is 33440341311.
11314304433 is a `hidden beast` number, since 1 + 1 + 314 + 304 + 43 + 3 = 666.
It is not a de Polignac number, because 11314304433 - 210 = 11314303409 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11314304397 and 11314304406.
It is not an unprimeable number, because it can be changed into a prime (11314304413) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 182083 + ... + 236183.
It is an arithmetic number, because the mean of its divisors is an integer number (717392520).
Almost surely, 211314304433 is an apocalyptic number.
It is an amenable number.
11314304433 is a deficient number, since it is larger than the sum of its proper divisors (5903116047).
11314304433 is a wasteful number, since it uses less digits than its factorization.
11314304433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55349 (or 55346 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 11314304433 its reverse (33440341311), we get a palindrome (44754645744).
The spelling of 11314304433 in words is "eleven billion, three hundred fourteen million, three hundred four thousand, four hundred thirty-three".
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