Base | Representation |
---|---|
bin | 10101000100110001… |
… | …01001010110011101 |
3 | 1002012111212012211121 |
4 | 22202120221112131 |
5 | 141132430220123 |
6 | 5110412450541 |
7 | 550244000146 |
oct | 124230512635 |
9 | 32174765747 |
10 | 11314304413 |
11 | 48866a2405 |
12 | 2239179a51 |
13 | 10b40932a9 |
14 | 794928acd |
15 | 46347675d |
hex | 2a262959d |
11314304413 has 2 divisors, whose sum is σ = 11314304414. Its totient is φ = 11314304412.
The previous prime is 11314304387. The next prime is 11314304459. The reversal of 11314304413 is 31440341311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9592635364 + 1721669049 = 97942^2 + 41493^2 .
It is a cyclic number.
It is not a de Polignac number, because 11314304413 - 229 = 10777433501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11314304483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657152206 + 5657152207.
It is an arithmetic number, because the mean of its divisors is an integer number (5657152207).
Almost surely, 211314304413 is an apocalyptic number.
It is an amenable number.
11314304413 is a deficient number, since it is larger than the sum of its proper divisors (1).
11314304413 is an equidigital number, since it uses as much as digits as its factorization.
11314304413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11314304413 its reverse (31440341311), we get a palindrome (42754645724).
The spelling of 11314304413 in words is "eleven billion, three hundred fourteen million, three hundred four thousand, four hundred thirteen".
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