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1131430508531 is a prime number
BaseRepresentation
bin10000011101101110100…
…000110111011111110011
311000011102100010000220022
4100131232200313133303
5122014132202233111
62223434430234055
7144512621433131
oct20355640673763
94004370100808
101131430508531
113a6923031284
1216334195592b
138290264140b
143ca938c6751
151e66ee992db
hex1076e8377f3

1131430508531 has 2 divisors, whose sum is σ = 1131430508532. Its totient is φ = 1131430508530.

The previous prime is 1131430508477. The next prime is 1131430508573. The reversal of 1131430508531 is 1358050341311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131430508531 - 234 = 1114250639347 is a prime.

It is a super-2 number, since 2×11314305085312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131430508491 and 1131430508500.

It is not a weakly prime, because it can be changed into another prime (1131430508431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565715254265 + 565715254266.

It is an arithmetic number, because the mean of its divisors is an integer number (565715254266).

Almost surely, 21131430508531 is an apocalyptic number.

1131430508531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131430508531 is an equidigital number, since it uses as much as digits as its factorization.

1131430508531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

Adding to 1131430508531 its reverse (1358050341311), we get a palindrome (2489480849842).

The spelling of 1131430508531 in words is "one trillion, one hundred thirty-one billion, four hundred thirty million, five hundred eight thousand, five hundred thirty-one".