Base | Representation |
---|---|
bin | 1010010010100101001010… |
… | …0111110000100111101110 |
3 | 1111001122021010000202011222 |
4 | 2210221102213300213232 |
5 | 2440333221440342032 |
6 | 40021421554343342 |
7 | 2245301434203023 |
oct | 244512247604756 |
9 | 44048233022158 |
10 | 11314330012142 |
11 | 3672420367453 |
12 | 132896228ab52 |
13 | 640c24039c91 |
14 | 2b188b93754a |
15 | 1494a1e37a12 |
hex | a4a529f09ee |
11314330012142 has 4 divisors (see below), whose sum is σ = 16971495018216. Its totient is φ = 5657165006070.
The previous prime is 11314330012133. The next prime is 11314330012151. The reversal of 11314330012142 is 24121003341311.
11314330012142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11314330012133) and next prime (11314330012151).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2828582503034 + ... + 2828582503037.
It is an arithmetic number, because the mean of its divisors is an integer number (4242873754554).
Almost surely, 211314330012142 is an apocalyptic number.
11314330012142 is a deficient number, since it is larger than the sum of its proper divisors (5657165006074).
11314330012142 is an equidigital number, since it uses as much as digits as its factorization.
11314330012142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5657165006073.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 11314330012142 its reverse (24121003341311), we get a palindrome (35435333353453).
The spelling of 11314330012142 in words is "eleven trillion, three hundred fourteen billion, three hundred thirty million, twelve thousand, one hundred forty-two".
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