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11314331209 is a prime number
BaseRepresentation
bin10101000100110001…
…01111111001001001
31002012111220120121001
422202120233321021
5141132432044314
65110413215001
7550244141236
oct124230577111
932174816531
1011314331209
114886710555
122239191461
1310b40a254c
1479493478d
1546347e674
hex2a262fe49

11314331209 has 2 divisors, whose sum is σ = 11314331210. Its totient is φ = 11314331208.

The previous prime is 11314331201. The next prime is 11314331221. The reversal of 11314331209 is 90213341311.

11314331209 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10281351609 + 1032979600 = 101397^2 + 32140^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314331209 - 23 = 11314331201 is a prime.

It is not a weakly prime, because it can be changed into another prime (11314331201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657165604 + 5657165605.

It is an arithmetic number, because the mean of its divisors is an integer number (5657165605).

Almost surely, 211314331209 is an apocalyptic number.

It is an amenable number.

11314331209 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314331209 is an equidigital number, since it uses as much as digits as its factorization.

11314331209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 28.

The spelling of 11314331209 in words is "eleven billion, three hundred fourteen million, three hundred thirty-one thousand, two hundred nine".