11314402043401 has 2 divisors, whose sum is σ = 11314402043402. Its totient is φ = 11314402043400.

The previous prime is 11314402043393. The next prime is 11314402043501. The reversal of 11314402043401 is 10434020441311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6470023053376 + 4844378990025 = 2543624^2 + 2200995^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314402043401 - 2³ = 11314402043393 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11314402043401.

It is not a weakly prime, because it can be changed into another prime (11314402043501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657201021700 + 5657201021701.

It is an arithmetic number, because the mean of its divisors is an integer number (5657201021701).

Almost surely, 2^{11314402043401} is an apocalyptic number.

It is an amenable number.

11314402043401 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314402043401 is an equidigital number, since it uses as much as digits as its factorization.

11314402043401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 11314402043401 its reverse (10434020441311), we get a palindrome (21748422484712).

The spelling of 11314402043401 in words is "eleven trillion, three hundred fourteen billion, four hundred two million, forty-three thousand, four hundred one".