Base | Representation |
---|---|
bin | 10000011101101111000… |
… | …101111101101011101001 |
3 | 11000011110000102002121222 |
4 | 100131233011331223221 |
5 | 122014142144430233 |
6 | 2223435414511425 |
7 | 144513100204664 |
oct | 20355705755351 |
9 | 4004400362558 |
10 | 1131440233193 |
11 | 3a6928573596 |
12 | 163345065575 |
13 | 8290466785a |
14 | 3ca94cd86db |
15 | 1e670c6a898 |
hex | 1076f17dae9 |
1131440233193 has 2 divisors, whose sum is σ = 1131440233194. Its totient is φ = 1131440233192.
The previous prime is 1131440233159. The next prime is 1131440233207. The reversal of 1131440233193 is 3913320441311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1125897132889 + 5543100304 = 1061083^2 + 74452^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131440233193 - 26 = 1131440233129 is a prime.
It is not a weakly prime, because it can be changed into another prime (1131440236193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565720116596 + 565720116597.
It is an arithmetic number, because the mean of its divisors is an integer number (565720116597).
Almost surely, 21131440233193 is an apocalyptic number.
It is an amenable number.
1131440233193 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131440233193 is an equidigital number, since it uses as much as digits as its factorization.
1131440233193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 1131440233193 in words is "one trillion, one hundred thirty-one billion, four hundred forty million, two hundred thirty-three thousand, one hundred ninety-three".
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