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11314433051 is a prime number
BaseRepresentation
bin10101000100110010…
…01000110000011011
31002012112002202021222
422202121020300123
5141132443324201
65110415322255
7550245044165
oct124231106033
932175082258
1011314433051
114886780019
12223922038b
1310b41099cc
1479495d935
1546349e91b
hex2a2648c1b

11314433051 has 2 divisors, whose sum is σ = 11314433052. Its totient is φ = 11314433050.

The previous prime is 11314432991. The next prime is 11314433069. The reversal of 11314433051 is 15033441311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11314433051 is a prime.

It is a super-2 number, since 2×113144330512 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11314433051.

It is not a weakly prime, because it can be changed into another prime (11314433551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657216525 + 5657216526.

It is an arithmetic number, because the mean of its divisors is an integer number (5657216526).

Almost surely, 211314433051 is an apocalyptic number.

11314433051 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314433051 is an equidigital number, since it uses as much as digits as its factorization.

11314433051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 11314433051 its reverse (15033441311), we get a palindrome (26347874362).

The spelling of 11314433051 in words is "eleven billion, three hundred fourteen million, four hundred thirty-three thousand, fifty-one".