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113144477 = 591917703
BaseRepresentation
bin1101011111001…
…11001010011101
321212220100001012
412233213022131
5212431110402
615121025005
72542466165
oct657471235
9255810035
10113144477
115895a136
1231a85165
131a5966c4
14110535a5
159dee452
hex6be729d

113144477 has 4 divisors (see below), whose sum is σ = 115062240. Its totient is φ = 111226716.

The previous prime is 113144467. The next prime is 113144489. The reversal of 113144477 is 774441311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113144477 - 26 = 113144413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113144467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 958793 + ... + 958910.

It is an arithmetic number, because the mean of its divisors is an integer number (28765560).

Almost surely, 2113144477 is an apocalyptic number.

It is an amenable number.

113144477 is a deficient number, since it is larger than the sum of its proper divisors (1917763).

113144477 is an equidigital number, since it uses as much as digits as its factorization.

113144477 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1917762.

The product of its digits is 9408, while the sum is 32.

The square root of 113144477 is about 10636.9392684174. The cubic root of 113144477 is about 483.6647682613.

Adding to 113144477 its reverse (774441311), we get a palindrome (887585788).

The spelling of 113144477 in words is "one hundred thirteen million, one hundred forty-four thousand, four hundred seventy-seven".

Divisors: 1 59 1917703 113144477