Base | Representation |
---|---|
bin | 10000011101110011011… |
… | …001110000110110110101 |
3 | 11000011122001110021111120 |
4 | 100131303121300312311 |
5 | 122014314202014110 |
6 | 2223450520254153 |
7 | 144514635555603 |
oct | 20356331606665 |
9 | 4004561407446 |
10 | 1131512532405 |
11 | 3a6965365002 |
12 | 163365311359 |
13 | 8291662ca58 |
14 | 3caa0758873 |
15 | 1e67729c870 |
hex | 10773670db5 |
1131512532405 has 24 divisors (see below), whose sum is σ = 1823731708512. Its totient is φ = 599068286592.
The previous prime is 1131512532391. The next prime is 1131512532413. The reversal of 1131512532405 is 5042352151311.
It is not a de Polignac number, because 1131512532405 - 29 = 1131512531893 is a prime.
It is a super-2 number, since 2×11315125324052 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1728007 + ... + 2291076.
It is an arithmetic number, because the mean of its divisors is an integer number (75988821188).
Almost surely, 21131512532405 is an apocalyptic number.
1131512532405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1131512532405 is a deficient number, since it is larger than the sum of its proper divisors (692219176107).
1131512532405 is an equidigital number, since it uses as much as digits as its factorization.
1131512532405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4019365 (or 4019228 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1131512532405 its reverse (5042352151311), we get a palindrome (6173864683716).
The spelling of 1131512532405 in words is "one trillion, one hundred thirty-one billion, five hundred twelve million, five hundred thirty-two thousand, four hundred five".
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