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11315132400 = 243521113233283
BaseRepresentation
bin10101000100110111…
…10011011111110000
31002012120102021121210
422202123303133300
5141133133214100
65110442320120
7550254016125
oct124233633760
932176367553
1011315132400
1148871084a0
1222394b9040
1310b42c3120
14794aa274c
1546358bc50
hex2a26f37f0

11315132400 has 480 divisors, whose sum is σ = 42916753152. Its totient is φ = 2512281600.

The previous prime is 11315132383. The next prime is 11315132431. The reversal of 11315132400 is 423151311.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 39982659 + ... + 39982941.

Almost surely, 211315132400 is an apocalyptic number.

11315132400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11315132400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21458376576).

11315132400 is an abundant number, since it is smaller than the sum of its proper divisors (31601620752).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11315132400 is a wasteful number, since it uses less digits than its factorization.

11315132400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 561 (or 550 counting only the distinct ones).

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 11315132400 its reverse (423151311), we get a palindrome (11738283711).

The spelling of 11315132400 in words is "eleven billion, three hundred fifteen million, one hundred thirty-two thousand, four hundred".