113152025600143 has 4 divisors (see below), whose sum is σ = 113195395486080. Its totient is φ = 113108655714208.

The previous prime is 113152025600093. The next prime is 113152025600179. The reversal of 113152025600143 is 341006520251311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113152025600143 - 2²⁵ = 113151992045711 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113152025600099 and 113152025600108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113152025600843) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21684939055 + ... + 21684944272.

It is an arithmetic number, because the mean of its divisors is an integer number (28298848871520).

Almost surely, 2^{113152025600143} is an apocalyptic number.

113152025600143 is a deficient number, since it is larger than the sum of its proper divisors (43369885937).

113152025600143 is an equidigital number, since it uses as much as digits as its factorization.

113152025600143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43369885936.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 113152025600143 its reverse (341006520251311), we get a palindrome (454158545851454).

The spelling of 113152025600143 in words is "one hundred thirteen trillion, one hundred fifty-two billion, twenty-five million, six hundred thousand, one hundred forty-three".