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11315225054977 is a prime number
BaseRepresentation
bin1010010010101000011111…
…1110000100111100000001
31111001201120111012122010121
42210222013332010330001
52440342040103224402
640022050450300241
72245332553014244
oct244520776047401
944051514178117
1011315225054977
11367283a613378
121328b71b87681
136410375b921c
142b193476325b
151495057d5837
hexa4a87f84f01

11315225054977 has 2 divisors, whose sum is σ = 11315225054978. Its totient is φ = 11315225054976.

The previous prime is 11315225054963. The next prime is 11315225055047. The reversal of 11315225054977 is 77945052251311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11105629565121 + 209595489856 = 3332511^2 + 457816^2 .

It is a cyclic number.

It is not a de Polignac number, because 11315225054977 - 215 = 11315225022209 is a prime.

It is not a weakly prime, because it can be changed into another prime (11315225024977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657612527488 + 5657612527489.

It is an arithmetic number, because the mean of its divisors is an integer number (5657612527489).

Almost surely, 211315225054977 is an apocalyptic number.

It is an amenable number.

11315225054977 is a deficient number, since it is larger than the sum of its proper divisors (1).

11315225054977 is an equidigital number, since it uses as much as digits as its factorization.

11315225054977 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2646000, while the sum is 52.

The spelling of 11315225054977 in words is "eleven trillion, three hundred fifteen billion, two hundred twenty-five million, fifty-four thousand, nine hundred seventy-seven".