Base | Representation |
---|---|
bin | 1010010010101000011111… |
… | …1110000100111100000001 |
3 | 1111001201120111012122010121 |
4 | 2210222013332010330001 |
5 | 2440342040103224402 |
6 | 40022050450300241 |
7 | 2245332553014244 |
oct | 244520776047401 |
9 | 44051514178117 |
10 | 11315225054977 |
11 | 367283a613378 |
12 | 1328b71b87681 |
13 | 6410375b921c |
14 | 2b193476325b |
15 | 1495057d5837 |
hex | a4a87f84f01 |
11315225054977 has 2 divisors, whose sum is σ = 11315225054978. Its totient is φ = 11315225054976.
The previous prime is 11315225054963. The next prime is 11315225055047. The reversal of 11315225054977 is 77945052251311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11105629565121 + 209595489856 = 3332511^2 + 457816^2 .
It is a cyclic number.
It is not a de Polignac number, because 11315225054977 - 215 = 11315225022209 is a prime.
It is not a weakly prime, because it can be changed into another prime (11315225024977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657612527488 + 5657612527489.
It is an arithmetic number, because the mean of its divisors is an integer number (5657612527489).
Almost surely, 211315225054977 is an apocalyptic number.
It is an amenable number.
11315225054977 is a deficient number, since it is larger than the sum of its proper divisors (1).
11315225054977 is an equidigital number, since it uses as much as digits as its factorization.
11315225054977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2646000, while the sum is 52.
The spelling of 11315225054977 in words is "eleven trillion, three hundred fifteen billion, two hundred twenty-five million, fifty-four thousand, nine hundred seventy-seven".
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