11315304000000 has 3360 divisors, whose sum is σ = 55156896482688. Its totient is φ = 2156544000000.

The previous prime is 11315303999977. The next prime is 11315304000041. The reversal of 11315304000000 is 40351311.

11315304000000 is a `hidden beast` number, since 1 + 131 + 530 + 4 + 0 + 0 + 0 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (3360).

It is a super-2 number, since 2×11315304000000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 335 ways as a sum of consecutive naturals, for example, 72071999922 + ... + 72072000078.

Almost surely, 2^{11315304000000} is an apocalyptic number.

11315304000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11315304000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27578448241344).

11315304000000 is an abundant number, since it is smaller than the sum of its proper divisors (43841592482688).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11315304000000 is an equidigital number, since it uses as much as digits as its factorization.

11315304000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 242 (or 198 counting only the distinct ones).

The product of its (nonzero) digits is 180, while the sum is 18.

Adding to 11315304000000 its reverse (40351311), we get a palindrome (11315344351311).

The spelling of 11315304000000 in words is "eleven trillion, three hundred fifteen billion, three hundred four million", and thus it is an aban number.