Search a number
-
+
11315305551299 is a prime number
BaseRepresentation
bin1010010010101000110011…
…0001001001010111000011
31111001201210002200021022212
42210222030301021113003
52440342221210120144
640022102443452335
72245334551145351
oct244521461112703
944051702607285
1011315305551299
113672880aa3462
121328b94b270ab
1364104b191499
142b19413187d1
1514950c8d649e
hexa4a8cc495c3

11315305551299 has 2 divisors, whose sum is σ = 11315305551300. Its totient is φ = 11315305551298.

The previous prime is 11315305551289. The next prime is 11315305551343. The reversal of 11315305551299 is 99215550351311.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11315305551299 is a prime.

It is a super-2 number, since 2×113153055512992 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11315305551259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657652775649 + 5657652775650.

It is an arithmetic number, because the mean of its divisors is an integer number (5657652775650).

Almost surely, 211315305551299 is an apocalyptic number.

11315305551299 is a deficient number, since it is larger than the sum of its proper divisors (1).

11315305551299 is an equidigital number, since it uses as much as digits as its factorization.

11315305551299 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 911250, while the sum is 50.

The spelling of 11315305551299 in words is "eleven trillion, three hundred fifteen billion, three hundred five million, five hundred fifty-one thousand, two hundred ninety-nine".