Base | Representation |
---|---|
bin | 110100101100010000… |
… | …0110010100111101100 |
3 | 101211001220110220221020 |
4 | 1221120200302213230 |
5 | 3323214430000102 |
6 | 123552101534140 |
7 | 11114031216540 |
oct | 1513040624754 |
9 | 354056426836 |
10 | 113154140652 |
11 | 43a96620723 |
12 | 19b1b114350 |
13 | a893accc17 |
14 | 5696071a20 |
15 | 2e23e87bbc |
hex | 1a588329ec |
113154140652 has 96 divisors (see below), whose sum is σ = 302729011200. Its totient is φ = 32224460352.
The previous prime is 113154140611. The next prime is 113154140677. The reversal of 113154140652 is 256041451311.
113154140652 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39799543 + ... + 39802385.
It is an arithmetic number, because the mean of its divisors is an integer number (3153427200).
Almost surely, 2113154140652 is an apocalyptic number.
113154140652 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113154140652 is an abundant number, since it is smaller than the sum of its proper divisors (189574870548).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113154140652 is a wasteful number, since it uses less digits than its factorization.
113154140652 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4235 (or 4233 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 113154140652 its reverse (256041451311), we get a palindrome (369195591963).
The spelling of 113154140652 in words is "one hundred thirteen billion, one hundred fifty-four million, one hundred forty thousand, six hundred fifty-two".
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