Base | Representation |
---|---|
bin | 10000011101111010000… |
… | …011000001111001100001 |
3 | 11000011220211020002200122 |
4 | 100131322003001321201 |
5 | 122020031221412114 |
6 | 2223505541530025 |
7 | 144520461256241 |
oct | 20357203017141 |
9 | 4004824202618 |
10 | 1131624013409 |
11 | 3a6a1228836a |
12 | 163396713915 |
13 | 82933763246 |
14 | 3cab1497b21 |
15 | 1e681e6de8e |
hex | 1077a0c1e61 |
1131624013409 has 2 divisors, whose sum is σ = 1131624013410. Its totient is φ = 1131624013408.
The previous prime is 1131624013339. The next prime is 1131624013417. The reversal of 1131624013409 is 9043104261311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1115780253025 + 15843760384 = 1056305^2 + 125872^2 .
It is a cyclic number.
It is not a de Polignac number, because 1131624013409 - 240 = 32112385633 is a prime.
It is a super-2 number, since 2×11316240134092 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1131624033409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565812006704 + 565812006705.
It is an arithmetic number, because the mean of its divisors is an integer number (565812006705).
Almost surely, 21131624013409 is an apocalyptic number.
It is an amenable number.
1131624013409 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131624013409 is an equidigital number, since it uses as much as digits as its factorization.
1131624013409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 1131624013409 in words is "one trillion, one hundred thirty-one billion, six hundred twenty-four million, thirteen thousand, four hundred nine".
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