11316433306433 has 2 divisors, whose sum is σ = 11316433306434. Its totient is φ = 11316433306432.

The previous prime is 11316433306333. The next prime is 11316433306457. The reversal of 11316433306433 is 33460333461311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6921066547264 + 4395366759169 = 2630792^2 + 2096513^2 .

It is a cyclic number.

It is not a de Polignac number, because 11316433306433 - 2¹⁴ = 11316433290049 is a prime.

It is a super-2 number, since 2×11316433306433² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11316433306333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5658216653216 + 5658216653217.

It is an arithmetic number, because the mean of its divisors is an integer number (5658216653217).

Almost surely, 2^{11316433306433} is an apocalyptic number.

It is an amenable number.

11316433306433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11316433306433 is an equidigital number, since it uses as much as digits as its factorization.

11316433306433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 41.

Adding to 11316433306433 its reverse (33460333461311), we get a palindrome (44776766767744).

The spelling of 11316433306433 in words is "eleven trillion, three hundred sixteen billion, four hundred thirty-three million, three hundred six thousand, four hundred thirty-three".