Base | Representation |
---|---|
bin | 1010010010101111001000… |
… | …0100001001001101010001 |
3 | 1111001220011112112202010210 |
4 | 2210223302010021031101 |
5 | 2440404211241431400 |
6 | 40022543233314333 |
7 | 2245424635400406 |
oct | 244536204111521 |
9 | 44056145482123 |
10 | 11317005030225 |
11 | 36735733400a4 |
12 | 132938a1059a9 |
13 | 64125c2b780b |
14 | 2b1a62d062ad |
15 | 1495abbd5950 |
hex | a4af2109351 |
11317005030225 has 12 divisors (see below), whose sum is σ = 18710781650096. Its totient is φ = 6035736016080.
The previous prime is 11317005030211. The next prime is 11317005030239. The reversal of 11317005030225 is 52203050071311.
It is an interprime number because it is at equal distance from previous prime (11317005030211) and next prime (11317005030239).
It is not a de Polignac number, because 11317005030225 - 211 = 11317005028177 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11317005030192 and 11317005030201.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 75446700127 + ... + 75446700276.
Almost surely, 211317005030225 is an apocalyptic number.
11317005030225 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11317005030225 is a deficient number, since it is larger than the sum of its proper divisors (7393776619871).
11317005030225 is a wasteful number, since it uses less digits than its factorization.
11317005030225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150893400416 (or 150893400411 counting only the distinct ones).
The product of its (nonzero) digits is 6300, while the sum is 30.
The spelling of 11317005030225 in words is "eleven trillion, three hundred seventeen billion, five million, thirty thousand, two hundred twenty-five".
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