Base | Representation |
---|---|
bin | 110100101101101000… |
… | …0001010001001011111 |
3 | 101211012002222112002000 |
4 | 1221123100022021133 |
5 | 3323313212042343 |
6 | 124000423133343 |
7 | 11115130035462 |
oct | 1513320121137 |
9 | 354162875060 |
10 | 113200112223 |
11 | 4400a56a860 |
12 | 19b325a4253 |
13 | a8a04a7833 |
14 | 569c1db2d9 |
15 | 2e28018ed3 |
hex | 1a5b40a25f |
113200112223 has 64 divisors (see below), whose sum is σ = 184219453440. Its totient is φ = 68131324800.
The previous prime is 113200112219. The next prime is 113200112281. The reversal of 113200112223 is 322211002311.
113200112223 is a `hidden beast` number, since 11 + 320 + 0 + 112 + 223 = 666.
It is not a de Polignac number, because 113200112223 - 22 = 113200112219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113200112196 and 113200112205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113200192223) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 38672986 + ... + 38675912.
It is an arithmetic number, because the mean of its divisors is an integer number (2878428960).
Almost surely, 2113200112223 is an apocalyptic number.
113200112223 is a deficient number, since it is larger than the sum of its proper divisors (71019341217).
113200112223 is a wasteful number, since it uses less digits than its factorization.
113200112223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3805 (or 3799 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 113200112223 its reverse (322211002311), we get a palindrome (435411114534).
The spelling of 113200112223 in words is "one hundred thirteen billion, two hundred million, one hundred twelve thousand, two hundred twenty-three".
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