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113200234400000 = 285511101127363
BaseRepresentation
bin11001101111010001111011…
…110000101000100100000000
3112211210211120222011111102002
4121233101323300220210000
5104314133040001300000
61040431245245243132
732562306223220606
oct3157217360504400
9484724528144362
10113200234400000
1133083a4a216280
1210842b695634a8
134b21975860447
141dd4cc60d3876
15d148e7c7c8d5
hex66f47bc28900

113200234400000 has 432 divisors, whose sum is σ = 311158197475776. Its totient is φ = 40755840000000.

The previous prime is 113200234399919. The next prime is 113200234400003. The reversal of 113200234400000 is 4432002311.

It is a super-3 number, since 3×1132002344000003 (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (113200234400003) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 888736319 + ... + 888863681.

It is an arithmetic number, because the mean of its divisors is an integer number (720273605268).

Almost surely, 2113200234400000 is an apocalyptic number.

113200234400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113200234400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (155579098737888).

113200234400000 is an abundant number, since it is smaller than the sum of its proper divisors (197957963075776).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113200234400000 is an equidigital number, since it uses as much as digits as its factorization.

113200234400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127516 (or 127482 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 113200234400000 its reverse (4432002311), we get a palindrome (113204666402311).

The spelling of 113200234400000 in words is "one hundred thirteen trillion, two hundred billion, two hundred thirty-four million, four hundred thousand".