Base | Representation |
---|---|
bin | 110100101101101000… |
… | …1001111110000011011 |
3 | 101211012010112000011212 |
4 | 1221123101033300123 |
5 | 3323313300203324 |
6 | 124000433213335 |
7 | 11115132333641 |
oct | 1513321176033 |
9 | 354163460155 |
10 | 113200397339 |
11 | 4400a744a97 |
12 | 19b3270124b |
13 | a8a0577543 |
14 | 569c273191 |
15 | 2e2807370e |
hex | 1a5b44fc1b |
113200397339 has 2 divisors, whose sum is σ = 113200397340. Its totient is φ = 113200397338.
The previous prime is 113200397311. The next prime is 113200397357. The reversal of 113200397339 is 933793002311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113200397339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113200397296 and 113200397305.
It is not a weakly prime, because it can be changed into another prime (113200394339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600198669 + 56600198670.
It is an arithmetic number, because the mean of its divisors is an integer number (56600198670).
Almost surely, 2113200397339 is an apocalyptic number.
113200397339 is a deficient number, since it is larger than the sum of its proper divisors (1).
113200397339 is an equidigital number, since it uses as much as digits as its factorization.
113200397339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 91854, while the sum is 41.
The spelling of 113200397339 in words is "one hundred thirteen billion, two hundred million, three hundred ninety-seven thousand, three hundred thirty-nine".
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