Base | Representation |
---|---|
bin | 110100101101101001… |
… | …0001001110011011111 |
3 | 101211012010222002022221 |
4 | 1221123102021303133 |
5 | 3323313330310403 |
6 | 124000442250211 |
7 | 11115134344063 |
oct | 1513322116337 |
9 | 354163862287 |
10 | 113200635103 |
11 | 4400a897696 |
12 | 19b327b6967 |
13 | a8a062b82a |
14 | 569c2d5aa3 |
15 | 2e280bddbd |
hex | 1a5b489cdf |
113200635103 has 4 divisors (see below), whose sum is σ = 113446190088. Its totient is φ = 112955080120.
The previous prime is 113200635101. The next prime is 113200635143. The reversal of 113200635103 is 301536002311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301536002311 = 919 ⋅328113169.
It is a cyclic number.
It is not a de Polignac number, because 113200635103 - 21 = 113200635101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113200635101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122776801 + ... + 122777722.
It is an arithmetic number, because the mean of its divisors is an integer number (28361547522).
Almost surely, 2113200635103 is an apocalyptic number.
113200635103 is a deficient number, since it is larger than the sum of its proper divisors (245554985).
113200635103 is an equidigital number, since it uses as much as digits as its factorization.
113200635103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 245554984.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 113200635103 its reverse (301536002311), we get a palindrome (414736637414).
The spelling of 113200635103 in words is "one hundred thirteen billion, two hundred million, six hundred thirty-five thousand, one hundred three".
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