Base | Representation |
---|---|
bin | 110100101101101001… |
… | …0010100000111101001 |
3 | 101211012011001020021202 |
4 | 1221123102110013221 |
5 | 3323313333133403 |
6 | 124000443213545 |
7 | 11115134611211 |
oct | 1513322240751 |
9 | 354164036252 |
10 | 113200677353 |
11 | 4400a916405 |
12 | 19b328172b5 |
13 | a8a0644b2a |
14 | 569c307241 |
15 | 2e280cb688 |
hex | 1a5b4941e9 |
113200677353 has 4 divisors (see below), whose sum is σ = 119158607760. Its totient is φ = 107242746948.
The previous prime is 113200677323. The next prime is 113200677377. The reversal of 113200677353 is 353776002311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113200677353 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113200677323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2978965175 + ... + 2978965212.
It is an arithmetic number, because the mean of its divisors is an integer number (29789651940).
Almost surely, 2113200677353 is an apocalyptic number.
It is an amenable number.
113200677353 is a deficient number, since it is larger than the sum of its proper divisors (5957930407).
113200677353 is an equidigital number, since it uses as much as digits as its factorization.
113200677353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5957930406.
The product of its (nonzero) digits is 79380, while the sum is 38.
Adding to 113200677353 its reverse (353776002311), we get a palindrome (466976679664).
The spelling of 113200677353 in words is "one hundred thirteen billion, two hundred million, six hundred seventy-seven thousand, three hundred fifty-three".
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