Base | Representation |
---|---|
bin | 10101000101011101… |
… | …10001100111100001 |
3 | 1002012220202221100111 |
4 | 22202232301213201 |
5 | 141140421333231 |
6 | 5111141051321 |
7 | 550344210601 |
oct | 124256614741 |
9 | 32186687314 |
10 | 11320105441 |
11 | 48899a4847 |
12 | 223b0b6b41 |
13 | 10b5344858 |
14 | 7955d8c01 |
15 | 463c204b1 |
hex | 2a2bb19e1 |
11320105441 has 2 divisors, whose sum is σ = 11320105442. Its totient is φ = 11320105440.
The previous prime is 11320105417. The next prime is 11320105457. The reversal of 11320105441 is 14450102311.
11320105441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10827443025 + 492662416 = 104055^2 + 22196^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320105441 - 25 = 11320105409 is a prime.
It is not a weakly prime, because it can be changed into another prime (11320105411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660052720 + 5660052721.
It is an arithmetic number, because the mean of its divisors is an integer number (5660052721).
Almost surely, 211320105441 is an apocalyptic number.
It is an amenable number.
11320105441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320105441 is an equidigital number, since it uses as much as digits as its factorization.
11320105441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 22.
Adding to 11320105441 its reverse (14450102311), we get a palindrome (25770207752).
The spelling of 11320105441 in words is "eleven billion, three hundred twenty million, one hundred five thousand, four hundred forty-one".
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