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11320111200002 = 2111673081140773
BaseRepresentation
bin1010010010111010101100…
…1101001111011100000010
31111002012012000100112000212
42210232223031033130002
52440432041431400002
640024215353314122
72245564623403103
oct244565315173402
944065160315025
1011320111200002
113674917726460
121329ab6405942
13641635992bb7
142b1c796683aa
151496de74c352
hexa4bab34f702

11320111200002 has 16 divisors (see below), whose sum is σ = 18634739401152. Its totient is φ = 5114693681520.

The previous prime is 11320111199993. The next prime is 11320111200031. The reversal of 11320111200002 is 20000211102311.

11320111200002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-4 number, since 4×113201112000024 (a number of 53 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11320111200002.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1540566713 + ... + 1540574060.

It is an arithmetic number, because the mean of its divisors is an integer number (1164671212572).

Almost surely, 211320111200002 is an apocalyptic number.

11320111200002 is a deficient number, since it is larger than the sum of its proper divisors (7314628201150).

11320111200002 is a wasteful number, since it uses less digits than its factorization.

11320111200002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3081140953.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 11320111200002 its reverse (20000211102311), we get a palindrome (31320322302313).

The spelling of 11320111200002 in words is "eleven trillion, three hundred twenty billion, one hundred eleven million, two hundred thousand, two".

Divisors: 1 2 11 22 167 334 1837 3674 3081140773 6162281546 33892548503 67785097006 514550509091 1029101018182 5660055600001 11320111200002