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1132012433 is a prime number
BaseRepresentation
bin100001101111001…
…0010001110010001
32220220002012010102
41003132102032101
54304243344213
6304154542145
740023642536
oct10336221621
92826065112
101132012433
11530a9a772
12277137955
131506ab956
14aa4b2d8d
15695ab158
hex43792391

1132012433 has 2 divisors, whose sum is σ = 1132012434. Its totient is φ = 1132012432.

The previous prime is 1132012423. The next prime is 1132012471. The reversal of 1132012433 is 3342102311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 648364369 + 483648064 = 25463^2 + 21992^2 .

It is a cyclic number.

It is not a de Polignac number, because 1132012433 - 28 = 1132012177 is a prime.

It is not a weakly prime, because it can be changed into another prime (1132012403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566006216 + 566006217.

It is an arithmetic number, because the mean of its divisors is an integer number (566006217).

Almost surely, 21132012433 is an apocalyptic number.

It is an amenable number.

1132012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132012433 is an equidigital number, since it uses as much as digits as its factorization.

1132012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1132012433 is about 33645.3924482982. The cubic root of 1132012433 is about 1042.1983923929.

Adding to 1132012433 its reverse (3342102311), we get a palindrome (4474114744).

The spelling of 1132012433 in words is "one billion, one hundred thirty-two million, twelve thousand, four hundred thirty-three".