Base | Representation |
---|---|
bin | 10101000101011101… |
… | …11000010111011001 |
3 | 1002012220211100021012 |
4 | 22202232320113121 |
5 | 141140423224311 |
6 | 5111141423305 |
7 | 550344354305 |
oct | 124256702731 |
9 | 32186740235 |
10 | 11320133081 |
11 | 4889a13594 |
12 | 223b10ab35 |
13 | 10b53542ca |
14 | 795604d05 |
15 | 463c2878b |
hex | 2a2bb85d9 |
11320133081 has 2 divisors, whose sum is σ = 11320133082. Its totient is φ = 11320133080.
The previous prime is 11320132997. The next prime is 11320133089. The reversal of 11320133081 is 18033102311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11275041856 + 45091225 = 106184^2 + 6715^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320133081 - 214 = 11320116697 is a prime.
It is a super-2 number, since 2×113201330812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11320133089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660066540 + 5660066541.
It is an arithmetic number, because the mean of its divisors is an integer number (5660066541).
Almost surely, 211320133081 is an apocalyptic number.
It is an amenable number.
11320133081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320133081 is an equidigital number, since it uses as much as digits as its factorization.
11320133081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 11320133081 its reverse (18033102311), we get a palindrome (29353235392).
The spelling of 11320133081 in words is "eleven billion, three hundred twenty million, one hundred thirty-three thousand, eighty-one".
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