Base | Representation |
---|---|
bin | 11001101111010011101011… |
… | …101011101100000111000001 |
3 | 112211211000102211111011220111 |
4 | 121233103223223230013001 |
5 | 104314200411202331001 |
6 | 1040432155444111321 |
7 | 32562403603646335 |
oct | 3157235353540701 |
9 | 484730384434814 |
10 | 113202112152001 |
11 | 33084823156134 |
12 | 108433b2395541 |
13 | 4b21bb48a45c2 |
14 | 1dd50236497c5 |
15 | d149a7a43851 |
hex | 66f4ebaec1c1 |
113202112152001 has 2 divisors, whose sum is σ = 113202112152002. Its totient is φ = 113202112152000.
The previous prime is 113202112151993. The next prime is 113202112152121. The reversal of 113202112152001 is 100251211202311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63165219999025 + 50036892152976 = 7947655^2 + 7073676^2 .
It is a cyclic number.
It is not a de Polignac number, because 113202112152001 - 23 = 113202112151993 is a prime.
It is not a weakly prime, because it can be changed into another prime (113202112132001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56601056076000 + 56601056076001.
It is an arithmetic number, because the mean of its divisors is an integer number (56601056076001).
Almost surely, 2113202112152001 is an apocalyptic number.
It is an amenable number.
113202112152001 is a deficient number, since it is larger than the sum of its proper divisors (1).
113202112152001 is an equidigital number, since it uses as much as digits as its factorization.
113202112152001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 113202112152001 its reverse (100251211202311), we get a palindrome (213453323354312).
The spelling of 113202112152001 in words is "one hundred thirteen trillion, two hundred two billion, one hundred twelve million, one hundred fifty-two thousand, one".
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