1132022021131 has 2 divisors, whose sum is σ = 1132022021132. Its totient is φ = 1132022021130.

The previous prime is 1132022021057. The next prime is 1132022021153. The reversal of 1132022021131 is 1311202202311.

It is a strong prime.

It is an emirp because it is prime and its reverse (1311202202311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1132022021131 - 2¹⁹ = 1132021496843 is a prime.

It is a super-2 number, since 2×1132022021131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1132022021099 and 1132022021108.

It is not a weakly prime, because it can be changed into another prime (1132022021171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566011010565 + 566011010566.

It is an arithmetic number, because the mean of its divisors is an integer number (566011010566).

Almost surely, 2^{1132022021131} is an apocalyptic number.

1132022021131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132022021131 is an equidigital number, since it uses as much as digits as its factorization.

1132022021131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1132022021131 its reverse (1311202202311), we get a palindrome (2443224223442).

The spelling of 1132022021131 in words is "one trillion, one hundred thirty-two billion, twenty-two million, twenty-one thousand, one hundred thirty-one".