Base | Representation |
---|---|
bin | 10000011110010001110… |
… | …010111000010101100001 |
3 | 11000012221120220220210021 |
4 | 100132101302320111201 |
5 | 122021340220324441 |
6 | 2224013253233441 |
7 | 144533366626606 |
oct | 20362162702541 |
9 | 4005846826707 |
10 | 1132022433121 |
11 | 3a70a7173a58 |
12 | 163488032881 |
13 | 82998170458 |
14 | 3cb0c36a6ad |
15 | 1e6a6e1e3d1 |
hex | 10791cb8561 |
1132022433121 has 8 divisors (see below), whose sum is σ = 1193533858080. Its totient is φ = 1070704137888.
The previous prime is 1132022433103. The next prime is 1132022433131. The reversal of 1132022433121 is 1213342202311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1132022433121 - 225 = 1131988878689 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1132022433131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48270391 + ... + 48293836.
It is an arithmetic number, because the mean of its divisors is an integer number (149191732260).
Almost surely, 21132022433121 is an apocalyptic number.
It is an amenable number.
1132022433121 is a deficient number, since it is larger than the sum of its proper divisors (61511424959).
1132022433121 is an equidigital number, since it uses as much as digits as its factorization.
1132022433121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96564863.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1132022433121 its reverse (1213342202311), we get a palindrome (2345364635432).
The spelling of 1132022433121 in words is "one trillion, one hundred thirty-two billion, twenty-two million, four hundred thirty-three thousand, one hundred twenty-one".
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