Base | Representation |
---|---|
bin | 10000011110010001110… |
… | …010111000010101001111 |
3 | 11000012221120220220202121 |
4 | 100132101302320111033 |
5 | 122021340220324403 |
6 | 2224013253233411 |
7 | 144533366626552 |
oct | 20362162702517 |
9 | 4005846826677 |
10 | 1132022433103 |
11 | 3a70a7173a41 |
12 | 163488032867 |
13 | 82998170443 |
14 | 3cb0c36a699 |
15 | 1e6a6e1e3bd |
hex | 10791cb854f |
1132022433103 has 2 divisors, whose sum is σ = 1132022433104. Its totient is φ = 1132022433102.
The previous prime is 1132022433053. The next prime is 1132022433131. The reversal of 1132022433103 is 3013342202311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1132022433103 - 229 = 1131485562191 is a prime.
It is a super-2 number, since 2×11320224331032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1132022433403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566011216551 + 566011216552.
It is an arithmetic number, because the mean of its divisors is an integer number (566011216552).
Almost surely, 21132022433103 is an apocalyptic number.
1132022433103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132022433103 is an equidigital number, since it uses as much as digits as its factorization.
1132022433103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1132022433103 its reverse (3013342202311), we get a palindrome (4145364635414).
The spelling of 1132022433103 in words is "one trillion, one hundred thirty-two billion, twenty-two million, four hundred thirty-three thousand, one hundred three".
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