Search a number
-
+
11321012012310 = 2325711131937178753
BaseRepresentation
bin1010010010111110000011…
…1001100100010100010110
31111002021111210101112012200
42210233200321210110112
52440440413033343220
640024445013025330
72245626142234050
oct244574071442426
944067453345180
1011321012012310
11367523a163040
12132a108025246
1364174a4b2230
142b1d231568d0
15149743889890
hexa4be0e64516

11321012012310 has 768 divisors, whose sum is σ = 42725237667840. Its totient is φ = 2001564794880.

The previous prime is 11321012012263. The next prime is 11321012012341. The reversal of 11321012012310 is 1321021012311.

11321012012310 is a `hidden beast` number, since 1 + 1 + 321 + 0 + 1 + 20 + 12 + 310 = 666.

It is a super-2 number, since 2×113210120123102 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 63243894 + ... + 63422646.

It is an arithmetic number, because the mean of its divisors is an integer number (55631819880).

Almost surely, 211321012012310 is an apocalyptic number.

11321012012310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11321012012310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21362618833920).

11321012012310 is an abundant number, since it is smaller than the sum of its proper divisors (31404225655530).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11321012012310 is a wasteful number, since it uses less digits than its factorization.

11321012012310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178853 (or 178850 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 11321012012310 its reverse (1321021012311), we get a palindrome (12642033024621).

Subtracting from 11321012012310 its reverse (1321021012311), we obtain a palindrome (9999990999999).

The spelling of 11321012012310 in words is "eleven trillion, three hundred twenty-one billion, twelve million, twelve thousand, three hundred ten".