Base | Representation |
---|---|
bin | 10000011110010110100… |
… | …011100110010010110111 |
3 | 11000020011011020020120121 |
4 | 100132112203212102313 |
5 | 122022021143010033 |
6 | 2224025225312411 |
7 | 144535356613144 |
oct | 20362643462267 |
9 | 4006134206517 |
10 | 1132102313143 |
11 | 3a7138272aaa |
12 | 1634aa935707 |
13 | 829ab88b039 |
14 | 3cb18c013cb |
15 | 1e6ade4c62d |
hex | 107968e64b7 |
1132102313143 has 4 divisors (see below), whose sum is σ = 1132112462400. Its totient is φ = 1132092163888.
The previous prime is 1132102313129. The next prime is 1132102313191. The reversal of 1132102313143 is 3413132012311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1132102313143 - 29 = 1132102312631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132102313543) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4905430 + ... + 5131027.
It is an arithmetic number, because the mean of its divisors is an integer number (283028115600).
Almost surely, 21132102313143 is an apocalyptic number.
1132102313143 is a deficient number, since it is larger than the sum of its proper divisors (10149257).
1132102313143 is a wasteful number, since it uses less digits than its factorization.
1132102313143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10149256.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1132102313143 its reverse (3413132012311), we get a palindrome (4545234325454).
The spelling of 1132102313143 in words is "one trillion, one hundred thirty-two billion, one hundred two million, three hundred thirteen thousand, one hundred forty-three".
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