Base | Representation |
---|---|
bin | 110100101101111011… |
… | …1011111000000000011 |
3 | 101211012211101021101212 |
4 | 1221123313133000003 |
5 | 3323323331440001 |
6 | 124001432120335 |
7 | 11115313463114 |
oct | 1513367370003 |
9 | 354184337355 |
10 | 113210421251 |
11 | 44015371114 |
12 | 19b35b360ab |
13 | a8a2676c55 |
14 | 569d72220b |
15 | 2e28da37bb |
hex | 1a5bddf003 |
113210421251 has 2 divisors, whose sum is σ = 113210421252. Its totient is φ = 113210421250.
The previous prime is 113210421119. The next prime is 113210421281. The reversal of 113210421251 is 152124012311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113210421251 - 210 = 113210420227 is a prime.
It is not a weakly prime, because it can be changed into another prime (113210421281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56605210625 + 56605210626.
It is an arithmetic number, because the mean of its divisors is an integer number (56605210626).
Almost surely, 2113210421251 is an apocalyptic number.
113210421251 is a deficient number, since it is larger than the sum of its proper divisors (1).
113210421251 is an equidigital number, since it uses as much as digits as its factorization.
113210421251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 113210421251 its reverse (152124012311), we get a palindrome (265334433562).
The spelling of 113210421251 in words is "one hundred thirteen billion, two hundred ten million, four hundred twenty-one thousand, two hundred fifty-one".
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