Base | Representation |
---|---|
bin | 10000011110010111100… |
… | …111001001010101001100 |
3 | 11000020012101112212020020 |
4 | 100132113213021111030 |
5 | 122022040211122200 |
6 | 2224031101022140 |
7 | 144535663252413 |
oct | 20362747112514 |
9 | 4006171485206 |
10 | 1132120020300 |
11 | 3a7147267715 |
12 | 1634b4854950 |
13 | 829b244a949 |
14 | 3cb1b2d047a |
15 | 1e6b0798ea0 |
hex | 107979c954c |
1132120020300 has 288 divisors, whose sum is σ = 3364119682560. Its totient is φ = 293843097600.
The previous prime is 1132120020289. The next prime is 1132120020307. The reversal of 1132120020300 is 30200212311.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1132120020300.
It is not an unprimeable number, because it can be changed into a prime (1132120020307) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1399406296 + ... + 1399407104.
It is an arithmetic number, because the mean of its divisors is an integer number (11680971120).
Almost surely, 21132120020300 is an apocalyptic number.
1132120020300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1132120020300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1682059841280).
1132120020300 is an abundant number, since it is smaller than the sum of its proper divisors (2231999662260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1132120020300 is a wasteful number, since it uses less digits than its factorization.
1132120020300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1473 (or 1466 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1132120020300 its reverse (30200212311), we get a palindrome (1162320232611).
The spelling of 1132120020300 in words is "one trillion, one hundred thirty-two billion, one hundred twenty million, twenty thousand, three hundred".
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