113214031400051 has 2 divisors, whose sum is σ = 113214031400052. Its totient is φ = 113214031400050.

The previous prime is 113214031399979. The next prime is 113214031400059. The reversal of 113214031400051 is 150004130412311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113214031400051 - 2²⁶ = 113213964291187 is a prime.

It is a super-3 number, since 3×113214031400051³ (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (113214031400059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56607015700025 + 56607015700026.

It is an arithmetic number, because the mean of its divisors is an integer number (56607015700026).

Almost surely, 2^{113214031400051} is an apocalyptic number.

113214031400051 is a deficient number, since it is larger than the sum of its proper divisors (1).

113214031400051 is an equidigital number, since it uses as much as digits as its factorization.

113214031400051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 113214031400051 its reverse (150004130412311), we get a palindrome (263218161812362).

The spelling of 113214031400051 in words is "one hundred thirteen trillion, two hundred fourteen billion, thirty-one million, four hundred thousand, fifty-one".