Base | Representation |
---|---|
bin | 1010010011000001110010… |
… | …0100111010010000000011 |
3 | 1111002101002120100122210102 |
4 | 2210300130210322100003 |
5 | 2440444440341330313 |
6 | 40025132220353015 |
7 | 2245663020366233 |
oct | 244603444722003 |
9 | 44071076318712 |
10 | 11322013230083 |
11 | 3675703338846 |
12 | 132a3473a576b |
13 | 641879a5779a |
14 | 2b1dba0ddcc3 |
15 | 1497a170ba58 |
hex | a4c1c93a403 |
11322013230083 has 2 divisors, whose sum is σ = 11322013230084. Its totient is φ = 11322013230082.
The previous prime is 11322013230023. The next prime is 11322013230133. The reversal of 11322013230083 is 38003231022311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11322013230083 - 218 = 11322012967939 is a prime.
It is not a weakly prime, because it can be changed into another prime (11322013230013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661006615041 + 5661006615042.
It is an arithmetic number, because the mean of its divisors is an integer number (5661006615042).
Almost surely, 211322013230083 is an apocalyptic number.
11322013230083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322013230083 is an equidigital number, since it uses as much as digits as its factorization.
11322013230083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 11322013230083 its reverse (38003231022311), we get a palindrome (49325244252394).
The spelling of 11322013230083 in words is "eleven trillion, three hundred twenty-two billion, thirteen million, two hundred thirty thousand, eighty-three".
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