Base | Representation |
---|---|
bin | 110100101110001111… |
… | …1111000011101101011 |
3 | 101211020120022022020011 |
4 | 1221130133320131223 |
5 | 3323334034330212 |
6 | 124002451112351 |
7 | 11115502500655 |
oct | 1513437703553 |
9 | 354216268204 |
10 | 113221011307 |
11 | 44020344628 |
12 | 19b395a26b7 |
13 | a8a4914261 |
14 | 56a0cbb6d5 |
15 | 2e29c964a7 |
hex | 1a5c7f876b |
113221011307 has 2 divisors, whose sum is σ = 113221011308. Its totient is φ = 113221011306.
The previous prime is 113221011283. The next prime is 113221011311. The reversal of 113221011307 is 703110122311.
It is a strong prime.
It is an emirp because it is prime and its reverse (703110122311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113221011307 - 27 = 113221011179 is a prime.
It is not a weakly prime, because it can be changed into another prime (113221011317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56610505653 + 56610505654.
It is an arithmetic number, because the mean of its divisors is an integer number (56610505654).
Almost surely, 2113221011307 is an apocalyptic number.
113221011307 is a deficient number, since it is larger than the sum of its proper divisors (1).
113221011307 is an equidigital number, since it uses as much as digits as its factorization.
113221011307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 22.
Adding to 113221011307 its reverse (703110122311), we get a palindrome (816331133618).
The spelling of 113221011307 in words is "one hundred thirteen billion, two hundred twenty-one million, eleven thousand, three hundred seven".
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